Problem 114: Flatten Binary Tree to Linked List
思路
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public void flatten(TreeNode root) {
if (root == null) return;
TreeNode left = root.left;
TreeNode right = root.right;
root.left = null;
flatten(left);
flatten(right);
root.right = left;
TreeNode cur = root;
while (cur.right != null) cur = cur.right;
cur.right = right;
}
}PreviousProblem 117: Populating Next Right Pointers in Each Node IINextProblem: Insert Node in a Binary Search Tree (LintCode)
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