Problem 64: Minimum Path Sum
思路
和前边的题目一样,矩阵型问题,重要的就是想清楚是怎么在这个矩阵中行走的。路线规划好,小心脚标。
public class Solution {
public int minPathSum(int[][] grid) {
if (grid == null || grid.length == 0 || grid[0].length == 0) {
return 0;
}
//state
int m = grid.length;
int n = grid[0].length;
int[][] f = new int[m][n];
//initiate
f[0][0] = grid[0][0];
for (int i = 1; i < n; i++) {
f[0][i] = f[0][i - 1] + grid[0][i];
}
for (int i = 1; i < m; i++) {
f[i][0] = f[i - 1][0] + grid[i][0];
}
//function
for (int i = 1; i < m; i++) {
for (int j = 1; j < n; j++) {
f[i][j] = Math.min(f[i - 1][j], f[i][j - 1]) + grid[i][j];
}
}
//answer
return f[m - 1][n - 1];
}
}
易错点
初始化是从1开始的
//initiate f[0][0] = grid[0][0]; for (int i = 1; i < n; i++) { f[0][i] = f[0][i - 1] + grid[0][i]; }
Min函数
Math.min(f[i - 1][j], f[i][j - 1])
这个函数写错好几次。第一是把之间的逗号写成加号;第二是总是把Math这个词忘掉
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